16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T48d,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Circle PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/mathematics/circle/m8vbdy2u","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Mathematics / Circle","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Circle PYQ with Solution","text":"The radius of the circle which cuts the circles x^2+y^2-4 x-4 y+7=0, x^2+y^2+4 x-4 y+6=0 and x^2+y^2+4 x+4 y+5=0 orthogonally is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Given, 1st circle =x^2+y^2-4 x-4 y+7=0 2nd circle =x^2+y^2+4 x-4 y+6=0 3rd circle =x^2+y^2+4 x+4 y+5=0 Now, find the center and radii of the given circles. 1st circle x^2+y^2-4 x-4 y+7=0 By complete the square \\begin{aligned} & (x-2)^2+(y-2)^2=2^2+2^2-7 \\\\ & (x-2)^2+(y-2)^2=1 \\end{aligned} Center C_1(2,2) Radius R_1=1 Similarly, 2nd Circle (x+2)^2+(y-2)^2=2 Center C_2(-2,2) and Radius R_2=\\sqrt{2} 3rd circle (x+2)^2+(y+2)^2=3 C_3(-2,-2), R_3=\\sqrt{3} Now, let the Radius R and center (a, b) be t..."}}}18:T5be,

Given, 1st circle

$$ =x^2+y^2-4 x-4 y+7=0 $$

2nd circle $=x^2+y^2+4 x-4 y+6=0$

3rd circle $=x^2+y^2+4 x+4 y+5=0$

Now, find the center and radii of the given circles.

1st circle $x^2+y^2-4 x-4 y+7=0$

By complete the square

$$ \begin{aligned} & (x-2)^2+(y-2)^2=2^2+2^2-7 \\ & (x-2)^2+(y-2)^2=1 \end{aligned} $$

Center

Circle

Continue this paper

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