16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T4dd,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 Circle PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/mathematics/circle/m8sw02l2","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Mathematics / Circle","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 Circle PYQ with Solution","text":"If the locus of the mid-point of the chords of the circle x^2+y^2=25, which subtend a right angle at the origin is given by \\frac{x^2}{\\alpha^2}+\\frac{y^2}{\\alpha^2}=1, then |\\alpha|=","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"Let mid-point be P(h, k) and origin O(0,0) is also the centre of the circle. Since, chord making right angle at origin and P is mid-point, O P will bisect the right angle. O P=r \\cos 45^{\\circ}, where r is radius of given circle. \\begin{array}{ll} \\Rightarrow & \\sqrt{(h-0)^2+(k-0)^2}=5 \\times \\frac{1}{\\sqrt{2}} \\\\ \\Rightarrow & h^2+k^2=\\left(\\frac{5}{\\sqrt{2}}\\right)^2=\\frac{25}{2} \\\\ \\therefore & \\quad O P=\\frac{5}{\\sqrt{2}} \\end{array} Let the coordinates of P be \\left(x_1, y_1\\right) O P=\\sq..."}}}18:T438,

Let mid-point be $P(h, k)$

and origin $O(0,0)$ is also the centre of the circle.

Since, chord making right angle at origin and $P$ is mid-point, $O P$ will bisect the right angle.

$O P=r \cos 45^{\circ}$, where $r$ is radius of given circle.

Circle

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