Ap EapcetCircleAP EAPCET 2024 - 20th May Morning ShiftMCQ+1 / -02024If the circle $x^2+y^2-8 x-8 y+28=0$ and $x^2+y^2-8 x-6 y+25-\alpha^2=0$ have only one common tangent, then $\alpha=$A$\alpha=4$B$\alpha=2$C$\alpha=1$D$\alpha=5$Check AnswerClear SelectionReveal AnswerShow Explanation
