16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T52f,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2024 States Of Matter PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2024/chemistry/states-of-matter/mb0d7am3","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Chemistry / States Of Matter","hasPart":{"@type":"Question","name":"Ap Eapcet 2024 States Of Matter PYQ with Solution","text":"60 \\mathrm{~cm}^3 of \\mathrm{SO}_2 gas diffused through a porous membrane in ' x ' min. Under similar conditions 360 \\mathrm{~cm}^3 of another gas (molar mass 4 \\mathrm{~g} \\mathrm{~mol}^{-1} ) diffused in ' y ' \\min. The ratio of x and y is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"B"},"comment":{"@type":"Comment","text":"Given the data: Volume of \\mathrm{SO}_2 (V_{\\mathrm{SO}_2}) = 60 \\mathrm{~cm}^3 Time for \\mathrm{SO}_2 (t_{\\mathrm{SO}_2}) = x minutes Molar mass of \\mathrm{SO}_2 (M_{\\mathrm{SO}_2}) = 64 \\mathrm{~g/mol} For the other gas: Volume (V_g) = 360 \\mathrm{~cm}^3 Time (t_g) = y minutes Molar mass (M_g) = 4 \\mathrm{~g/mol} We apply Graham's law of diffusion, which states that the rate of diffusion (r) is inversely proportional to the square root of the molar mass, as shown below: r \\propto \\frac{1}{\\sq..."}}}18:T42f,

Given the data:

Volume of $\mathrm{SO}_2$ ($V_{\mathrm{SO}_2}$) = $60 \mathrm{~cm}^3$

Time for $\mathrm{SO}_2$ ($t_{\mathrm{SO}_2}$) = $x$ minutes

Molar mass of $\mathrm{S

States Of Matter

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