Ap Eapcet
Definite Integration
AP EAPCET 2023 - 15th May Morning Shift
MCQ+1 / -02023
If $[x]$ is the greatest integer not exceeding $x$, then \(\int_{-0.5}^{1.5} x^2[x] d x=\)
Ap Eapcet
AP EAPCET 2023 - 15th May Morning Shift
If $[x]$ is the greatest integer not exceeding $x$, then \(\int_{-0.5}^{1.5} x^2[x] d x=\)