16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T48f,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2021 Hyperbola PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2021/mathematics/hyperbola/1lk74w9ij","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Mathematics / Hyperbola","hasPart":{"@type":"Question","name":"Ap Eapcet 2021 Hyperbola PYQ with Solution","text":"If the focal chord of the hyperbola subtends a right angle at the center, then its eccentricity is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"C"},"comment":{"@type":"Comment","text":"Let focal chord be latusrectum then it is given that it subtends 90^\\circ at its centre. Image Here, equation of hyperbola is \\frac{x^2}{a^2}-\\frac{y^2}{b^2}=1 ...... (i) So eccentricity, e=\\sqrt{1+\\frac{b^2}{a^2}} End points of latus rectum, L=\\left(a e, \\frac{b^2}{a}\\right) and L^{\\prime}\\left(a e, \\frac{-b^2}{a}\\right) Centre (0,0) \\because In \\triangle L C L^{\\prime} by Pythagoras theorem \\begin{aligned} & (L C)^2+\\left(L^{\\prime} C\\right)^2=\\left(L L^{\\prime}\\right)^2 \\\\ & (a e-0)^2+\\left(..."}}}18:T4f2,

Let focal chord be latusrectum then it is given that it subtends 90$$^\circ$$ at its centre.

Image

Here, equation of hyperbola is

$$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$$ ...... (i)

So eccentricity, $$e=\sqrt{1+\frac{b^2}{a^2}}$$

End points of latus rectum, $$L=\left(a e, \frac{b^2}{a}\right)$$ and $$L^{\prime}\left(a e, \frac{-b^2}{a}\

Hyperbola

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