16:I[8216,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"BackButton"] 17:I[1553,["972","static/chunks/972-b28da0de92681928.js","47","static/chunks/47-a7f06e9eda1ac756.js","115","static/chunks/app/%5Bexam%5D/questions/%5Byear%5D/%5Bsubject%5D/%5Bchapter%5D/%5BquestionId%5D/page-7b6f0a12b9cc0206.js"],"QuestionViewer"] 15:T488,{"@context":"https://schema.org","@type":"Quiz","name":"Ap Eapcet 2021 Circle PYQ with Solution","url":"https://pyq-test-series-platform-alsjdcxu2-sameers-projects-41c5a71e.vercel.app/ap-eapcet/questions/2021/mathematics/circle/1lk5pjarb","educationalLevel":"Entrance exam preparation","about":"Ap Eapcet / Mathematics / Circle","hasPart":{"@type":"Question","name":"Ap Eapcet 2021 Circle PYQ with Solution","text":"The equation of the pair of straight lines parallel to x-axis and touching the circle x^2+y^2-6 x-4 y-12=0 is","eduQuestionType":"mcq","acceptedAnswer":{"@type":"Answer","text":"A"},"comment":{"@type":"Comment","text":"Equation parallel to X-axis is given as y=a or y-a=0 ....... (i) If Eq. (i) touches the circle x^2+y^2-6 x-4 y-12=0 ..... (ii) Then, Eq. (i) becomes tangent to circle. Centre of Eq. (ii) is (3,2) Radius of Eq. (ii) is \\sqrt{9+4+12}=5 Then, perpendicular distance from centre to line (i) is radius i.e. Perpendicular distance between (3,2) and y-a=0 is equal to 5 \\begin{aligned} & \\text { i.e. } \\quad\\left|\\frac{2-a}{l}\\right|=5 \\\\ & \\Rightarrow \\quad 2-a= \\pm 5 \\\\ & \\Rightarrow \\quad a=7,-3 \\\\ \\e..."}}}18:T4fe,

Equation parallel to $$X$$-axis is given as

$$y=a$$

or $$y-a=0$$ ....... (i)

If Eq. (i) touches the circle

$$x^2+y^2-6 x-4 y-12=0$$ ..... (ii)

Then, Eq. (i) becomes tangent to circle.

Centre of Eq. (ii) is $$(3,2)$$

Radius of Eq. (ii) is $$\sqrt{9+4+12}=5$$

Circle

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