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Current Electricity

AIIMS 2019

MCQ+1 / -0.332019

For a wire \(\frac{R}{\ell}=\frac{1}{2}\) and length of wire is \(\ell=5 \mathrm{~cm}\). If potential difference of \(\mathrm{l} \mathrm{V}\) is applied across it, then current through wire will be (\(R=\) Resistance)

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